2x^2-34x-36=0

Solution for 2x^2-34x-36=0 equation:

2x^2-34x-36=0

a = 2; b = -34; c = -36;
Δ = b2-4ac
Δ = -342-4·2·(-36)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-38}{2*2}=\frac{-4}{4}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+38}{2*2}=\frac{72}{4}
=18
$